(4x/35+5x)/(x)/(49-x^2)

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Solution for (4x/35+5x)/(x)/(49-x^2) equation: 


D( x )

x = 0

49-x^2 = 0

x = 0

x = 0

49-x^2 = 0

49-x^2 = 0

-1*x^2 = -49 // : -1

x^2 = 49

x^2 = 49 // ^ 1/2

abs(x) = 7

x = 7 or x = -7

x in (-oo:-7) U (-7:0) U (0:7) U (7:+oo)

(((4*x)/35+5*x)/x)/(49-x^2) = 0

(179/35*x)/(x*(49-x^2)) = 0

179/35*x = 0 // : 179/35

x = 0

x in { 0} 

x belongs to the empty set

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